卖萌的弱渣

I am stupid, I am hungry.

UTF-8 Validation

A character in UTF8 can be from 1 to 4 bytes long, subjected to the following rules:

  1. For 1-byte character, the first bit is a 0, followed by its unicode code.
  2. For n-bytes character, the first n-bits are all one’s, the n+1 bit is 0, followed by n-1 bytes with most significant 2 bits being 10.

This is how the UTF-8 encoding would work:

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   Char. number range  |        UTF-8 octet sequence
      (hexadecimal)    |              (binary)
   --------------------+---------------------------------------------
   0000 0000-0000 007F | 0xxxxxxx
   0000 0080-0000 07FF | 110xxxxx 10xxxxxx
   0000 0800-0000 FFFF | 1110xxxx 10xxxxxx 10xxxxxx
   0001 0000-0010 FFFF | 11110xxx 10xxxxxx 10xxxxxx 10xxxxxx

Given an array of integers representing the data, return whether it is a valid utf-8 encoding.

Note:

The input is an array of integers. Only the least significant 8 bits of each integer is used to store the data. This means each integer represents only 1 byte of data.

Example 1:

data = [197, 130, 1], which represents the octet sequence: 11000101 10000010 00000001.

Return true. It is a valid utf-8 encoding for a 2-bytes character followed by a 1-byte character.

Example 2:

data = [235, 140, 4], which represented the octet sequence: 11101011 10001100 00000100.

Return false. The first 3 bits are all one’s and the 4th bit is 0 means it is a 3-bytes character.

The next byte is a continuation byte which starts with 10 and that’s correct.

But the second continuation byte does not start with 10, so it is invalid.

Solution

(Utf-8-Validation.py) download
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class Solution(object):
    def validUtf8(self, data):
        """
        :type data: List[int]
        :rtype: bool
        """
        masks = [0x0, 0x80, 0xE0, 0xF0, 0xF8]
        bits = [0x0, 0x0, 0xC0, 0xE0, 0xF0]
        while data:
            for x in (4, 3, 2, 1, 0):
                if data[0] & masks[x] == bits[x]:
                    break
            if x == 0 or len(data) < x:
                return False
            for y in range(1, x):
                if data[y] & 0xC0 != 0x80:
                    return False
            data = data[x:]
        return True