Given an array of non-negative integers, you are initially positioned at the first index of the array.

Each element in the array represents your maximum jump length at that position.

Your goal is to reach the last index in the minimum number of jumps.

For example:

Given array A = [2,3,1,1,4]

The minimum number of jumps to reach the last index is 2. (Jump 1 step from index 0 to 1, then 3 steps to the last index.)

Note:

You can assume that you can always reach the last index.

Solution

• 贪心： 因为nums[i] 是最大能到的区域
• cur: 当前能覆盖的最大区域
• last: 按照ret走过的区域

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class Solution(object):
    def jump(self, nums):
        """
        :type nums: List[int]
        :rtype: int
        """

        last = 0
        cur = 0
        ret = 0

        for i in range(len(nums)):
            if i > last:
                last = cur
                ret += 1
            cur = max(cur, nums[i] + i)
        return ret