Given a linked list, determine if it has a cycle in it.
Follow up:
Space: O(1)
Solution
 (Linked-List-Cycle.py) download
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  | # Definition for singly-linked list.
# class ListNode(object):
#     def __init__(self, x):
#         self.val = x
#         self.next = None
class Solution(object):
    def hasCycle(self, head):
        """
        :type head: ListNode
        :rtype: bool
        """
        if head == None or head.next == None:
            return False
        slow = head
        fast = head.next
        while fast != None and fast.next != None:
            if slow == fast:
                return True
            slow = slow.next
            fast = fast.next.next
        return False
  |